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AUT Bernhard Lorenz (1800 Provisional)
   

          
          
          
          
          
          
          
          
  
1.e4 c6 2.d4 d5 3.Nc3 dxe4 4.Nxe4 Bf5 5.Ng3 Bg6 6.Nf3 e6 7.h4 h6 8.h5 Bh7 9.Bd3 Bxd3 10.Qxd3 Nf6 11.Bd2 Nbd7 12.O-O-O a5 13.Rde1 Bb4 14.a3 Bxd2+ 15.Nxd2 O-O 16.Nge4 Qc7 17.Nxf6+ Nxf6 18.Ne4 Nxe4 19.Rxe4
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KAZ Arman Bulatov (1753)
  
     

 

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