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AUT Karl Mantl (1881)
AUT Austria 		   

          
          
          
          
          
          
          
          
  
1.d4 d5 2.c4 e6 3.Nf3 c6 4.e3 Nf6 5.Bd3 dxc4 6.Bxc4 Bd6 7.O-O Nbd7 8.Qc2 O-O 9.Nc3 Qc7 10.Bd2 b5 11.Bd3 Bb7 12.a3 e5 13.Rac1 exd4 14.exd4 a6 15.b4 Rfe8 16.Rfe1 h6 17.Ne2 Nd5 18.Qb1 N7f6 19.Ng3 Nf4 20.Ne4 Qd8 21.Bc2 Rb8 22.Kf1 Ne6 23.Qb2 Nxe4 24.Bxe4 Rc8 25.Rc3 Rc7 26.Qc2 Qf6 27.Bxc6 Bxc6 28.Rxc6 Rec8 29.Rxc7 Rxc7 30.Qd3 Qd8 31.d5 Nf4 32.Bxf4 Bxf4 33.g3 Bd6 34.Nd4 Be7 35.Qe4 Bf6 36.Nc6 Qd6 37.Qe8+ Kh7 38.Rd1 h5 39.Kg2 h4 40.Rd3 g6 41.Qe4 hxg3 42.hxg3 Kg8 43.Qe8+ Kg7 44.Rd1 Bb2 45.f4 Rd7 46.Kf1 Bf6 47.Ke2 Rc7 48.Ke3 Qf8 49.Qxf8+ Kxf8 50.g4 Bb2 51.Ke4 Ke8 52.Rd2 Bg7 53.Ra2 Rc8 54.a4 Bf8 55.axb5 axb5 56.Kf3 f6 57.Ra5 Kd7 58.Rxb5 Kd6 59.Nd4 Rc4 60.Ne6 Be7 61.Ke3 f5 62.Kd3 Rc1 63.gxf5 gxf5 64.Ng7 Kc7 65.Nxf5 Bf8 66.Nd4 Rd1+ 67.Ke4 Re1+ 68.Kf5 Bd6 69.Ne6+ Kc8 70.Rb6 Bb8 71.Nc5 Rd1 72.Rc6+ Kd8 73.d6 Rd2 74.b5 Ba7 75.Nb7+ Ke8 76.Rc8+ Kf7 77.Nd8+ Ke8 78.Ne6+ Kf7 79.Rf8#
1-0

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CZE František Šindelář (2011)
CZE Czech Republic 		 
     

 

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