ICCF



AUT Peter Steinkellner (1800 Provisional)
   

          
          
          
          
          
          
          
          
 
1.e4 e5 2.Nf3 Nc6 3.Bb5 a6 4.Bxc6 bxc6 5.Nc3 d6 6.d4 exd4 7.Qxd4 c5 8.Qd3 Ne7 9.Bf4 Ng6 10.Bg3 Be6 11.O-O-O f6 12.h4 Be7 13.Qe2 Bg4 14.Qc4 Qc8 15.Nd5 Bd8 16.h5 Ne5 17.Nxe5 fxe5 18.h6 g5 19.f3 Be6 20.Qd3 a5 21.Kb1 a4 22.c4 Qd7 23.Nc3 Qf7 24.Nd5 Rg8 25.Ne3 Rg6 26.Rdf1 Qf8
1/2-1/2

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CZE František Skalický (2173)
 

     

 


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