ICCF



CFR Pavel Alekseevich Danenkov (2300 Provisional)
   

          
          
          
          
          
          
          
          
 
1.d4 Nf6 2.Bg5 Ne4 3.Bf4 c5 4.f3 Qa5+ 5.c3 Nf6 6.Nd2 cxd4 7.Nb3 Qb6 8.Qxd4 Nc6 9.Qxb6 axb6 10.Nd4 e5 11.Nxc6 exf4 12.Nd4 d5 13.g3 Bd6 14.Nb5 Bb8 15.gxf4 Bxf4 16.e3 Bb8 17.a3 g5 18.h3 O-O 19.Kf2 h5 20.Bd3 h4 21.Ne2 Nh5 22.Rhg1 f6 23.f4 Bxh3 24.Nbd4 Kf7 25.c4 dxc4
1/2-1/2

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GER Horst Arnold (2250)
 

     

 


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