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SCO Martin E. Hardwick (1278)
   

          
          
          
          
          
          
          
          
  
1.b3 Nf6 2.Bb2 e6 3.e3 Be7 4.c4 a6 5.Nf3 O-O 6.Be2 d6 7.O-O Bd7 8.d4 d5 9.Nbd2 c6 10.Qc2 Re8 11.Ne5 Bc8 12.f4 Nbd7 13.Bd3 Nxe5 14.fxe5 Ne4 15.Nxe4 dxe4 16.Bxe4 g6 17.Rf3 Rf8 18.Raf1 Qc7 19.Qf2 b6 20.Rxf7 Rxf7 21.Qxf7+ Kh8 22.Qe8+ Kg7 23.Rf7+ Kh6 24.Rxh7+ Kxh7 25.Qxg6+ Kh8 26.Qh7#
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FRA Bernard Schulz (1951)
  
     

 

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