ICCF



SWE Roland Lindahl (1846)
SWE Sweden
   

          
          
          
          
          
          
          
          
 
1.e4 e5 2.Nf3 Nf6 3.Nxe5 d6 4.Nf3 Nxe4 5.d4 d5 6.Bd3 Nf6 7.O-O Be7 8.Bf4 O-O 9.h3 Bd6 10.Be5 c6 11.Re1 Bc7 12.c4 Re8 13.Nc3 Ba5 14.Bxf6 Rxe1+ 15.Qxe1 gxf6 16.cxd5 cxd5 17.Qc1 Bxc3 18.Qh6 f5 19.Ng5 Be6 20.bxc3 Qd7
1-0

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AUS Peter S. Maylott (1958)
AUS Australia
 

     

 


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